Concept lesson

Electrochemistry: from reaction to cell potential

Balance the electron transfer, then build the reaction quotient.

The central idea

Identify oxidation and reduction and combine them into a balanced overall reaction. The number n in the Nernst equation is the electrons transferred by that balanced reaction. Pure solids and pure liquids have activity one and are omitted from the usual reaction quotient.

A worked example

For Zn + Cu²⁺ → Zn²⁺ + Cu, n = 2 and Q = [Zn²⁺]/[Cu²⁺]. At 298 K, E = E° − (0.0592/2) log Q. If the concentration ratio is 100, the cell potential is 0.0592 V below its standard value.

A common mistake

Do not multiply an electrode potential by the coefficient used to balance electrons. Potential is an intensive quantity.

Try the idea

These original practice questions also appear in the foundation mock. Attempt them before opening the explanation.

Question 24 · ElectrochemistrySingle correct · +3 / −1

For Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), E°cell = 1.10 V. At 298 K, [Zn²⁺] = 1.0 M and [Cu²⁺] = 0.010 M. Use 0.0592 V for 2.303RT/F. Ecell is approximately:

Select one answer.
Question 25 · ElectrochemistrySingle correct · +3 / −1

How much copper is deposited when 0.100 mol electrons pass through CuSO₄ solution with 100% current efficiency? Use Cu = 63.5.

Select one answer.
Question 26 · ElectrochemistrySingle correct · +3 / −1

For a galvanic reaction with n = 2 and E°cell = 0.500 V, ΔG° is approximately: F = 96485 C mol⁻¹.

Select one answer.
Question 52 · ElectrochemistryMultiple correct · +6

For an operating galvanic cell, which statements are correct?

Select all correct answers.

What to do next

Explain your answer aloud, then find a related question in an official paper. If you can only follow a worked solution but cannot start a fresh question, revisit the central idea and try again without the notes.

Apply it to an official paper